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Discussion Starter · #1 ·
Hi, i am new to PHP but i have some common knowledge to recognizing commands and such.

in my page i have code like this

Code:
<div  class="page_column page_column_first" id="page_column_1" style="width:  499px;"><div class="page_block_container"  id="page_block_759"><div class="disignBoxFirst">
    <div class="boxFirstHeader"><div class="dbTitle">Up and Coming</div></div>

     <div class="boxContent"><div  class="dbContentHtml"><p>This is a placeholder for up and  coming news to be edited at News  Time.</p></div></div>
So whatever class it is linked to say "boxContent" which is the name of a section on a .css file on the server, i want it take the information under that header and place it on that same line and doing something like
Code:
preg_replace
class="boxContent with style="border: 0px;
background-color: transparent;
margin:10px auto 5px;"

Can somebody write something like that for me please or help me with it? It's basically taking the css rule and converting it to inline Thanks
 

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Discussion Starter · #3 ·
not change it, just get that rule and replace it with the class text and class name for example

<div class ="sys_top_menu">

capture it and get it and display it as

<div style ="what the css rule was on the css file(s)>
 

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like this
Code:
preg_replace('/<div class ="sys_top_menu">/', '<div style ="what the css rule was on the css file(s)>', $variable)
changing "what the css rule was on the css file(s)" to what ever it is you want? and changing $variable to the php variable you have the code in
 
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